3254. Find the Power of K-Size Subarrays I

class Solution {
public:
    vector<int> resultsArray(vector<int>& nums, int k)
    {
        if (k == 1) return nums;
        vector<int> res;

        int n = nums.size();

        int i = 1, consecutiveSize = 1;
        while (i < n)
        {
            if (nums[i - 1] + 1 == nums[i])
            {
                consecutiveSize++;
            }
            else
            {
                consecutiveSize = 1;
            }
            if (i + 1 >= k)
            {
                if (consecutiveSize >= k)
                {
                    res.push_back(nums[i]);
                }
                else
                {
                    res.push_back(-1);
                }
            }
            i++;
        }
        return res;
    }
};

• T: $O(N)$
• S: $O(N)$